Java Program to Check Leap Year

What is a Leap Year?

The Earth takes approximately 365.25 days to complete one orbit around the Sun, and this is known as a solar year. However, to simplify the calendar, we round the days in a year to 365. To account for the additional fractional day, we add one extra day to the calendar approximately every four years. This results in a leap year, which contains 366 days instead of the usual 365 days. The extra day is inserted in February, making it a month with 29 days instead of the usual 28 days.

How to determine whether a year is a leap year

If it is evenly divisible by 4
Unless it is also evenly divisible by 100
Unless it is also evenly divisible by 400

The year 2000 was a leap year, because it obeys all three rules 1, 2, and 3, and therefore was a leap year.

Algorithm

If year is not divisible by 4 then it is a common year
Else if year is not divisible by 100 then it is a leap year
Else if year is not divisible by 400 then it is a common year
Else it is a leap year

How to Check Leap Year in Java?

You can write a program to check if a given year is a leap year or not. A leap year is a year that is divisible by 4, except for years that are divisible by 100. However, years divisible by 400 are also considered leap years.

Following is a Java program to check if a year is a leap year:

import java.util.Scanner; public class LeapYearChecker { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a year: "); int year = scanner.nextInt(); if (isLeapYear(year)) { System.out.println(year + " is a leap year."); } else { System.out.println(year + " is not a leap year."); } scanner.close(); } public static boolean isLeapYear(int year) { if ((year % 4 == 0 && year % 100 != 0) (year % 400 == 0)) { return true; } else { return false; } } }

In this program, we first take input from the user for the year to be checked. Then, we call the isLeapYear() method to determine whether the year is a leap year or not.

The isLeapYear() method checks the conditions for a leap year using if-else statements. If the year is divisible by 4 and not divisible by 100, or it is divisible by 400, then it returns true, indicating that the year is a leap year. Otherwise, it returns false, indicating that the year is not a leap year.

Conclusion

You can run this program and input different years to check if they are leap years or not.

Next > Java Program to Check if a String/Number is Palindrome

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